JQuery自定义函数校验密码强度

function passValidate(){
    var password=$password.val().trim()
    if(password===""){
       $mima.addClass('has-error')
       $password.after('<lable class="help-block">密码不能为空</lable>')
        return false
    }
    //密码为八位及以上并且字母数字特殊字符三项都包括
    var strongRegex = new RegExp("^(?=.{8,})(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.*\\W).*$", "g");
    //密码为七位及以上并且字母、数字、特殊字符三项中有两项，强度是中等
    var mediumRegex = new RegExp("^(?=.{7,})(((?=.*[A-Z])(?=.*[a-z]))|((?=.*[A-Z])(?=.*[0-9]))|((?=.*[a-z])(?=.*[0-9]))).*$", "g");
    var enoughRegex = new RegExp("(?=.{6,}).*", "g");
    if (false == enoughRegex.test(password)) {
    } else if (strongRegex.test(password)) {
         $password.after('<lable class="help-block"><span class="qiang">密码强度强</span></lable>')
    } else if (mediumRegex.test(password)) {
        $password.after('<lable class="help-block" ><span class="zhong">密码强度中</span></lable>')
    } else {
        $password.after('<lable class="help-block" ><span class="ruo">密码强度弱</span></lable>')
    }

    return true
}

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